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| author | Peter Zijlstra <peterz@infradead.org> | 2026-03-12 14:48:44 +0100 |
|---|---|---|
| committer | Peter Zijlstra <peterz@infradead.org> | 2026-06-30 10:56:51 +0200 |
| commit | 4161cb2d867b2210b447afc4a941ab4b96e1bd13 (patch) | |
| tree | 6aa97377fbb6566542028e20d0b17aca710d51e6 /tools/perf/scripts/python/task-analyzer.py | |
| parent | 4f166adb5cb0525d9e32d45729fd8f28c80acbee (diff) | |
sched/fair: Add cgroup_mode switch
The effective task weight (W_t') for a task in cgroup g on CPU n is given by:
W_t
W_t' = W_g * F_g_n * ----------
\Sum W_t_n
Where W_g is the group's weight (cpu.weight), F_g_n is the fraction of the
group weight for CPU n and W_t/W is the relative weight of this task against
all other tasks in the same group on the same CPU.
Furthermore, this makes:
\Sum W_t_n
F_g_n = ----------
\Sum W_t
The fraction of weight inside the group of CPU n against the whole group.
The problem is with F_g_n, the primary goal of this fraction is to make sure
that the relative weight of tasks, when distributed over CPUs is maintained.
For example, consider 4 (equal weight) tasks and 2 CPUs with a 1:3
distribution, then if F_g_n would simply be 1 (no weight re-distribution) the
effective relative weights (W_t') of the tasks in our group would be:
CPU0 CPU1
W_g W_g/3
W_g/3
W_g/3
IOW, the lucky task on CPU0 would get an equal amount of weight as all 3 tasks
on CPU1 combined. However, with the weight redistribution, this becomes:
CPU0 CPU1
W_g/4 W_g/4
W_g/4
W_g/4
All tasks are equal weight (as intended). However, as is already evident from
this example, the more CPUs you add, the smaller F_g_n becomes, which creates a
disparity against tasks not in our group.
Specifically:
avg(F_g_n) ~ 1/N
This leads to a weight mismatch in the hierarchy. IOW tasks cannot compete
fairly across hierarchy levels.
*Notably*, what is meant by avg(F_g_n) being proportional to 1/N is that when
there are at least N runnable tasks, the average of this fraction tends to 1/N.
For a hierarchy of depth d, this gets even worse, since that gets terms on the
order of:
avg(F_g_n)^d ~ 1/(N^d)
Given fixed point arithmetic, this also leads to numerical trouble.
However, the meaning of "cpu.weight" is simple and intiutive: the total weight
of the cgroup. But as explored above, there is deception in this simplicity.
Prepare to add a few alternative methods for distributing weight.
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Link: https://patch.msgid.link/20260605124051.338602724%40infradead.org
Diffstat (limited to 'tools/perf/scripts/python/task-analyzer.py')
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